x^2=16x-56

Solution for x^2=16x-56 equation:

x^2=16x-56

We move all terms to the left:

x^2-(16x-56)=0

We get rid of parentheses

x^2-16x+56=0

a = 1; b = -16; c = +56;
Δ = b2-4ac
Δ = -162-4·1·56
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4\sqrt{2}}{2*1}=\frac{16-4\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4\sqrt{2}}{2*1}=\frac{16+4\sqrt{2}}{2}
$